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请问用staad怎样计算玻璃的变形!
xfx2003ok






积分 117
帖子 127
2003-10-24 12:51    顶部


请问用staad怎样计算玻璃的变形!
delta






积分 809
帖子 534
2003-10-25 10:14    QQ 顶部


使用板单元来模拟玻璃啊,材料特性指定为玻璃的,当然要把板单元尽量划分成小块,可以使用STAAD中自动划分工具
xfx2003ok






积分 117
帖子 127
2003-10-25 14:36    顶部


如果在板开孔,那么支座怎么定义呢?
STEELGIRL






积分 118
帖子 61
2003-10-27 10:54    顶部


我想那要看洞开在什么地方,什么样子了
xfx2003ok






积分 117
帖子 127
2003-10-27 21:54    顶部


是点玻钢爪的位置,用204的爪,支座可以放在玻璃的边角上吗?
delta






积分 809
帖子 534
2003-10-29 13:40    QQ 顶部


可以细分网格,开洞没问题,STAAD 2003增加了MESHER的程序,这些工作可以自动完成
delta






积分 809
帖子 534
2003-10-29 13:42    QQ 顶部


然后可以导入STAAD.PRO中
xfx2003ok






积分 117
帖子 127
2003-10-30 20:49    顶部


谢谢!那么请问支座定义在哪个位置比较合适呀?
delta






积分 809
帖子 534
2003-11-4 13:39    QQ 顶部


支座按实际情况定义吧
xfx2003ok






积分 117
帖子 127
2003-11-7 11:37    顶部


在玻璃的里有很多应力,例如有SQX 、SQY、 MAX-ABSOLUTE、 MAX-TOP等,应该考虑哪几个为主?
delta






积分 809
帖子 534
2003-11-19 08:50    QQ 顶部


没有直接算过玻璃,但是最大绝对值肯定是首先要控制的,平面外弯矩和剪力也应该控制,还有膜应力也应该控制
xfx2003ok






积分 117
帖子 127
2003-11-30 12:34    顶部


要是要算拉索,预应力在哪里加呀?是在member force 里还是在定义member属性里?
fortran95






积分 31
帖子 15
2003-11-30 14:20    顶部


三角形单元的性态并不好啊,为啥不划成四边形的?
delta






积分 809
帖子 534
2003-12-1 08:37    QQ 顶部


索的预应力在“特殊构件”-“梁单元”-“缆索构件”里面添加。
xfx2003ok






积分 117
帖子 127
2003-12-1 18:03    顶部


为什么我们总工程师说是在member-force 里面加的呢?
他说如果象你说的那样加,是不准确的呀!
你那里有什么根据呢?
delta






积分 809
帖子 534
2003-12-2 08:58    QQ 顶部


您做个例子就可以看出来了,我是REI的工程师。
xfx2003ok






积分 117
帖子 127
2003-12-2 12:33    顶部


我觉得也是,不过在看拉索结果的时候,拉索本身产生的应力为0喔,不过对结构就产生了力,为什么是这样的呀???
delta






积分 809
帖子 534
2003-12-3 11:59    QQ 顶部


可能时拉锁受压了!查一查!
xfx2003ok






积分 117
帖子 127
2003-12-4 12:32    顶部


我觉得不是这样,因为我看应力是在于应力状态下的!
delta






积分 809
帖子 534
2003-12-4 13:33    QQ 顶部


轴力有吗?
tigeryang






积分 34
帖子 19
2003-12-6 23:10    顶部


staadpro真是强啊。板能自动mesh了?这在很多软件中不多见啊
不知道建模是否方便,此功能有无说明书看看?谢谢!
  
玻璃可以用S11最大主应力来较核强度
  
支座放在圆的四周就可...btw,,另有个软件strand7可以模拟point contact单元,,这样可以把钢爪和玻璃的接触也模拟进去
  
索的预应力在结构受力变形后会损失很多。。。我也碰到此问题但不可能是压的应该是正常的吧?顺便也请教一下高手
whoami






积分 1355
帖子 745
2003-12-7 10:50    顶部


下面是STAAD中对索的计算的一些说明,希望能对诸位有所帮助。
  
   
  
When all of the members, elements and support springs are linear except for cable and/or preloaded truss members, then this analysis type may be used.  This analysis is based on applying the load in steps with equilibrium iterations to convergence at each step.  The step sizes start small and gradually increase (15-20 steps is the default).  Iteration continues at each step until the change in deformations is small before proceeding to the next step.  If not converged, then the solution is stopped.  The user can then select more steps or modify the structure and rerun.
  
   
  
Structures can be artificially stabilized during the first few load steps in case the structure is initially unstable (in the linear, small displacement, static theory sense).
  
   
  
The user has control of the number of steps, the maximum number of iterations per step, the convergence tolerance, the artificial stabilizing stiffness, and the minimum amount of stiffness remaining after a cable sags.
  
   
  
This method assumes small displacement theory for all members/trusses/elements other than cables & preloaded trusses.  The cables and preloaded trusses can have large displacement and moderate/large strain.  Cables and preloaded trusses may carry tension and compression but cables have a reduced E modulus if not fully taut.  Pretension is the force necessary to stretch the cable/truss from its unstressed length to enable it to fit between the two end joints.  Alternatively, you may enter the unstressed length for cables.
  
   
  
The current nonlinear cable analysis procedure can result in compressive forces in the final cable results.  The procedure was developed for structures, loadings, and pretensioning loads that will result in sufficient tension in every cable for all loading conditions.  The possibility of compression was considered acceptable in the initial implementation because most design codes strongly recommend cables to be in tension to avoid the undesirable dynamic effects of a slack cable such as galloping, singing, or pounding.  The engineer must specify initial preloading tensions which will ensure that all cable results are in tension.  In addition this procedure is much more reliable and efficient than general nonlinear algorithms.  To minimize the compression the SAGMIN input variable can be set to a small value such as 0.01, however that can lead to a failure to converge unless many more steps are specified and a higher equilibrium iteration limit is specified.  SAGMIN values below 0.70 generally requires some adjustments of the other input parameters to get convergence.
  
   
  
Currently the cable and truss are not automatically loaded by selfweight, but the user should ensure that selfweight is applied in every load case.  Do not enter component load cases such as wind only; every case must be realistic.  Member loads will be lumped at the ends for cables and trusses.  Temperature load may also be applied to the cables and trusses.  It is OK to break up the cable/truss into several members and apply forces to the intermediate joints.  Y-up is assumed and required.
  
   
  
The member force printed for the cable is Fx and is along the chord line between the displaced positions of the end joints.
  
   
  
The analysis sequence is as follows:
  
Compute the unstressed length of the nonlinear members based on joint coordinates, pretension, and temperature.
  
Member/Element/Cable stiffness is formed. Cable stiffness is from EA/L and the sag formula plus a geometric stiffness              based on current tension.
  
Assemble and solve the global matrix with the percentage of the total applied load used for this load step.
  
Perform equilibrium iterations to adjust the change in directions of the forces in the nonlinear cables, so that the structure is  in static equilibrium in the deformed position.  If force changes are too large or convergence criteria not met within 15 iterations then stop the analysis.
  
Go to step 2 and repeat with a greater percentage of the applied load.  The nonlinear members will have an updated orientation with new tension and sag effects.
  
After 100% of the applied load has converged then proceed to compute member forces, reactions, and static check.  Note that the static check is not exactly in balance due to the displacements of the applied static equivalent joint loads.
  
   
  
The load cases in a non linear cable analysis must be separated by the CHANGE command and PERFORM CABLE ANALYSIS command. The SET NL command must be provided to specify the total number of primary load cases. There may not be any Multi-linear springs, compression only, PDelta, NONLINEAR,  or dynamic cases.
  
   
  
Also for cables and preloaded trusses:
  
Do not use Member Offsets.
  
Do not include the end joints in Master/Slave command.
  
Do not connect to inclined support joints.
  
Y direction must be up.
  
Do not impose displacements.
  
Do not use Support springs in the model.
  
Applied loads do not change global directions due to displacements.
  
Do not apply Prestress load, Fixed end load.
  
Do not use Load Combination command to combine cable analysis results.  Use a primary case with Repeat Load instead.
如要用STAAD2003 中新增添的非线性缆索分析引擎计算实际的拉索结构的话,我想应该注意如下的问题:
  1)不能使用通常的荷载组合的方法(即GB50009中的线性组合的方法得出控制内力)
  2)拉索和玻璃的安全系数究竟取多大合适,有一些资料中拉索可取到5。玻璃的许用应力是多少就不得而知了。
  3)尚无法对非线性索进行动力分析(如反应谱和时程分析),如该结果要算地震的话。
whoami






积分 1355
帖子 745
2003-12-7 10:56    顶部


delta :
    你好!
    呵呵,我想我认识你。
    你那里有没有使用缆索分析的算例?如有的话,能贴一个出来吗?多谢
delta






积分 809
帖子 534
2003-12-8 09:07    QQ 顶部


who先生的帖子今天是铺天盖地了,呵呵,我的email delta210@sian.com。
贴个小小的缆索构件例子吧。
whoami






积分 1355
帖子 745
2003-12-12 14:15    顶部


谢谢delta 兄!
  
xfx2003ok






积分 117
帖子 127
2003-12-12 15:33    顶部


我觉得看玻璃强度应该看应力绝对值最大的那个
但是计算索的时候,加预应力最好用温度来加
sap也是这样算的呀
member force里面加是不对的
在member属性加我就不知道,可能对吧:)
xfx2003ok






积分 117
帖子 127
2003-12-16 14:42    顶部


请问在钢结构设计的FYLD里面应该输入多少呢?是310000吗?
delta






积分 809
帖子 534
2003-12-17 10:55    QQ 顶部


fyld 钢材屈服强度,根据单位制决定,美国请查看ASTM A36,中国请查阅钢结构规范 fy
xfx2003ok






积分 117
帖子 127
2003-12-17 20:19    顶部


加入用美国规范计算,但是是采用中国的fy,这里面的折减系数是多少呀?就是说假如用Q235,应该在fyld输入多少呢?是310000吧!?
delta






积分 809
帖子 534
2003-12-18 11:29    QQ 顶部


那还要看单位制啊,应该是235 N/mm2,表示最小屈服应力点或者屈服应力。我个人认为不需要折减,除非中国钢材屈服应力达不到235N/mm2!
 


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